Skip to main content

How to Solve "TypeError: 'set' object is not subscriptable" in Python

The TypeError: 'set' object is not subscriptable error in Python occurs when you try to access elements of a set using indexing (square brackets []), which is not supported. Sets are unordered collections of unique elements, and therefore do not have a defined order or indices.

This guide explains why this error occurs and provides the correct ways to work with set data.

Understanding Subscriptability and Sets​

In Python, "subscriptable" means that you can access elements of an object using square brackets with an index or key, like this: my_object[index_or_key]. Lists, tuples, strings, and dictionaries are subscriptable:

  • Lists: my_list[2] (accesses the element at index 2)
  • Tuples: my_tuple[0] (accesses the element at index 0)
  • Strings: my_string[5] (accesses the character at index 5)
  • Dictionaries: my_dict['key'] (accesses the value associated with the key 'key')

Sets, however, are not subscriptable. Sets are:

  • Unordered: Elements have no defined order.
  • Unique: Sets can not contain duplicate elements.

Because sets are unordered, the concept of an "index" doesn't apply. There's no "first" or "third" element in a set in the way there is in a list or tuple.

my_set = {'a', 'b', 'c'}

# ⛔️ TypeError: 'set' object is not subscriptable
# print(my_set[0])  # This causes the error

Solutions​

If you're getting the TypeError: 'set' object is not subscriptable error, you likely need to use a different data structure or a different approach. Here are the common solutions:

Converting a Set to a List (If Order Matters)​

If you need to access elements by index and the order of elements is important, convert the set to a list:

my_set = {'a', 'b', 'c'}
my_list = list(my_set)  # Convert the set to a list

print(my_list)      # Output: ['a', 'c', 'b'] (order *might* be different)
print(my_list[0])   # Output: 'a' (or whatever is at index 0 now)
warning

The order of elements in a set is arbitrary and not guaranteed. When you convert a set to a list, the order of elements in the list might be different from the order in which you added them to the set. If order is important, you shouldn't have been using a set in the first place.

Converting a Set to a Tuple (If Order Matters and Immutability is Desired)​

If you need to access elements by index, and the order of elements is important, and you do not need to modify the elements use a tuple()

my_set = {'a', 'b', 'c'}
my_tuple = tuple(my_set)  # Convert set to tuple
print(my_tuple[0])        # Output: a
  • Tuples are ordered and indexed collections, unlike sets.

Using a List Instead of a Set (If Order and/or Duplicates are Needed)​

If you find yourself needing to index into a collection, a set is likely the wrong data structure. Consider using a list instead, if order matters and/or you need to allow duplicate elements:

my_list = ['a', 'b', 'c']  # Use a list from the start
print(my_list[0])          # Output: a (This is perfectly valid)

Using a Dictionary Instead of a Set​

If you need to assign values to the items, use a dictionary:

my_dict = {'name': 'Alice', 'age': 30}

print(my_dict['name']) # Output: "Alice"
print(my_dict['age'])  # Output: 30
  • The dictionaries will preserve the order of the key-value pairs.
  • You can access the values assigned to keys using square bracket notation.

Using in for Membership Testing (Correct Set Usage)​

If you simply want to check if a value is present in a set, use the in operator. This is what sets are designed for, and it's very efficient:

my_set = {'a', 'b', 'c'}

print('a' in my_set)  # Output: True
print('d' in my_set)  # Output: False

This is the correct way to use a set. You don't need indexing for this.

Iterating Over a Set​

You can iterate over the elements of a set using a for loop. You just can't access them by index within the loop:

my_set = {'a', 'b', 'c'}

for element in my_set:
    print(element)  # Output: a, b, c (in some arbitrary order)

my_set.add('d')
my_set.remove('b')
print(my_set) # Output: {'c', 'a', 'd'}

Conclusion​

The TypeError: 'set' object is not subscriptable error occurs because sets are unordered collections and don't support indexing.

  • If you need indexing, use a list or a tuple.
  • If you genuinely need a set (for uniqueness and fast membership testing), use the in operator to check for the presence of an element, or iterate over the set using a for loop without attempting to use indices.
  • If you must have both uniqueness and indexing, consider using an ordered set implementation (available in some third-party libraries) or a dictionary where the keys are the unique elements and the values are their indices (though this is often a sign that you should rethink your data structure).

Table of Contents